Given:
m∠NRQ = 60°
To find:
The angle measure of minor arc NQ
Solution:
The inscribed angle is half of the intercepted arc.

Multiply by 2 on both sides.


Substitute m∠NRQ = 60°.


The measure of minor arc NQ is 120°.
Answer:
72 kg
Step-by-step explanation:
For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?
We are given the ratio
cement: sand:stones
= 1:2:4
The sum of proportion =
1 + 2 + 4 = 7
We are given the kg of sand = 144kg
Step 1
We find the total kg of cement, sand and stones = x
Using the proportion of sand,
2/7 of x = 144kg
2/7 × x = 144kg
2x/7 = 144kg
Cross Multiply
2x = 7 × 144kg
x = 7 × 144kg/2
x = 504kg
Therefore the total kg of cement, sand and stone = 504kg
Step 2
The amount of cement required is calculated as:
1/7 × 504 kg = 72 kg
Therefore, 72kg of cement is required.
X = half width of tent
Tan(40) = 6/x
x = 6/Tan(40) = 7.15
2x = 14.30 feet the width of the tent
D) 16.
Espero que esto ayude hermano.
Answer:
5/8
Step-by-step explanation:
28x + 4 can be factorised because 28 is a multiple of 4
so it can become
4(7x+1)
35x + 5 can be also factorised because 35 is a multiple of 5
5(7x+1)
we can now rewrite the expression as
6/4(7x+1) * 5(7x+1)/12
we can “eliminate” the two 7x+1 and simplify 6 with 12
so it remains
1/4 * 5/2 = 5/8