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exis [7]
2 years ago
14

shows a map of Olivia's trip to a coffee shop. She gets on her bike at Loomis and then rides south 0.9mi to Broadway. She turns

east onto Broadway, rides 0.8 mi to where Broadway turns, and then continues another 1.2mi to the shop. What is the magnitude of the total displacement of her trip?
Physics
1 answer:
Andreas93 [3]2 years ago
3 0

The  magnitude of the total displacement of her trip is 2.2 miles.

<h3>Total displacement of Olivia's trip</h3>

The magnitude of the total displacement of her trip is calculated as follows;

Total east journey = 0.8 mi + 1.2 mi = 2 mi

Resultant displacement = √(y² + x²)

Resultant displacement = √(0.9² + 2²)

Resultant displacement = 2.2 mi

Thus, the  magnitude of the total displacement of her trip is 2.2 miles.

Learn more about displacement here: brainly.com/question/321442

#SPJ1

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Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

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