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White raven [17]
3 years ago
14

What elements on the periodic table are metalloids?

Physics
1 answer:
seropon [69]3 years ago
7 0

Answer:

The term 'mettaloid' is normally applied to a group of between six and nine elements ;

  1. Boron
  2. Silicon
  3. Germanium
  4. Arsenic
  5. Antimony
  6. Tellurium, and possibly
  7. Bismuth
  8. Polonium
  9. Astatine

are found near the center of the P-block or main block of the periodic table.

Explanation:

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Answer:

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Explanation:

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Two bar magnets are hung from metal rods and held in the position shown below.
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The correct diagram is C.

In fact, the magnetic force works as the electrostatic force: like poles repel each other, while opposite poles attract each other. In this example, we have two magnets one next to each other, and we see that the north pole of one magnet is close to the south pole of the other: therefore, the two poles attract each other, so the two magnets will move closer, as in diagram C.

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What was the hiker's average velocity during Part A of the hike?
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Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. The magnitude of q1 is 3 times the magnitu
Alex777 [14]

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge q_{1} between the two charges.

q_{1} = magnitude of charge on one charge

q_{2} = magnitude of charge on other charge

q_{1} = 3 q_{2}

E_{1} = Electric field by charge q_{1} at point "a"

E_{2} = Electric field by charge q_{2} at point "a"


Electric field by charge q_{1} at point "a" is given as

E_{1} = kq_{1} /r²

Electric field by charge q_{2} at point "a" is given as

E_{2} = kq_{2} /(d-r)²

For the electric field to be zero at point "a"

E_{2} = E_{1}

kq_{2} /(d-r)² = kq_{1} /r²

q_{2} /(d-r)² = 3q_{2} /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm


8 0
3 years ago
What is the velocity of a dog who travels south 50 meters in 9 seconds
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Roughly 5.6 meters per second (m/s)

Velocity is determined by distance divided by time. In this case, we divide 50 meters by 9 seconds, giving us the dog’s velocity of 5.55555 (repeating) meters per second. We can round to 5.6 m/s if needed.
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