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icang [17]
2 years ago
11

What is 6÷2(1+2)someone help ​

Mathematics
1 answer:
In-s [12.5K]2 years ago
6 0
Hopes this helps:

Answer: 9

1. Simplify 1 + 2 to 3.

6 divided by 2 times 3


2. Simplify 6 divided by 2 to 3.

3 times 3


3. Simplify.

9
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I am thinking it is times 2 everytime
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Given right triangle ABCABC with altitude \overline{BD}
Alex

Answer:

x = 2\sqrt{11}

Step-by-step explanation:

AD = 4

AC = 11

DC = 11 - 4 = 7

First, find BD using the right triangle altitude theorem:

BD = \sqrt{AD*DC}

Plug in the values

BD = \sqrt{4*7}

BD = 2\sqrt{7}

Use pythagorean theorem to find x:

x² = AD² + BD²

Plug in the values

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 16 + (4*7)

x^2 = 16 + 28

x^2 = 44

Take the square root of both sides

\sqrt{x^2} = \sqrt{44}

x = \sqrt{44}

x = \sqrt{4 * 11}

x = 2\sqrt{11}

6 0
3 years ago
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Write the verbal sentence as an equation:
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In circle E shown, chords AB and CD are parallel. (a) What does this information tell you about 1  and 2  ? Why? (b) Given you
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Find the taylor polynomial t3(x) for the function f centered at the number
inysia [295]

Answer:

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

Step-by-step explanation:

We are given that

f(x)=7tan^{-1}(x)

a=1

T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}

Substitute n=3 and a=1

t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}

f(x)=7tan^{-1}(x)

f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}

Where tan^{-1}(1)=\frac{\pi}{4}

f'(x)=\frac{7}{1+x^2}

Using the formula

\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}

f'(1)=\frac{7}{2}

f''(x)=\frac{-14x}{(1+x^2)^2}

f''(1)=-\frac{7}{2}

f''(x)=-14x(x^2+1)^{-2}

f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})

By using the formula

(uv)'=u'v+v'u

f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}

f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}

f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}

Substitute the values

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

7 0
3 years ago
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