In a random group of 23 people, what is the chance in percent that two people have the same birthday ?

Mathematics

2 answers:

yawa3891 [41]2 years ago

3 0

Answer: 50%

Step-by-step explanation:

Don't believe it's true? You can test it and see mathematical probability in action! The birthday paradox, also known as the birthday problem, states that in a random group of 23 people, there is about a 50 percent chance that two people have the same birthday.

ivanzaharov [21]2 years ago

3 0

50%

Because there around 7.594 billion people so to have 23 people in a group together it is 50% that 2 people with have the same birthday

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There are a total of 100 balloons. If the ratio of yellow balloons to blue balloons is 8 to 12, how many of them are yellow

Ivanshal [37]

If you have 8 yellow balloons for every 12 blue balloons, then if you have 20 balloons in total, 8 out of 20 of those balloons will be yellow. Then you can set up this ratio:

$\frac{8yellow}{20total} = \frac{Xyellow}{100total}$

Then, you can use either cross multiplication or multiply the numerator and denominator by the same number to help solve for x. Personally, I prefer cross multiplication, so that's what I'll show you here:

$\frac{8yellow}{20total} = \frac{Xyellow}{100total} \\ 8yellow*100total=20total*Xyellow$

Finally, solve for x:

$8yellow*100total=20total*Xyellow \\ 8*100=20*x \\ 800=20x \\ 800/20=20x/20 \\ x=40yellow$

If you had 100 balloons, you will have 40 yellow balloons.

Hope this helps!!

6 0

2 years ago

Reposting this because no body gave me the equation. An equation would be appreciated :)

o-na [289]

bring the like terms together,

$\frac{6q}{5} + \frac{4q}{5} \leqslant 28 + 3 + 3 - 3$