In a random group of 23 people, what is the chance in percent that two people have the same birthday ?

Mathematics

2 answers:

yawa3891 [41]2 years ago

3 0

Answer: 50%

Step-by-step explanation:

Don't believe it's true? You can test it and see mathematical probability in action! The birthday paradox, also known as the birthday problem, states that in a random group of 23 people, there is about a 50 percent chance that two people have the same birthday.

ivanzaharov [21]2 years ago

3 0

50%

Because there around 7.594 billion people so to have 23 people in a group together it is 50% that 2 people with have the same birthday

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Step2247 [10]

Answer:

$A = 297\pi$

Step-by-step explanation:

To solve this problem we need to be familiar with the formula for the surface area of a cone:

$A = \pi r(r + \sqrt{h^2+r^2})$

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

$r = \frac{d}{2}\\r = \frac{18}{2}\\r = 9 cm$

To calculate the height of the cone, we must use the Pythagorean Theorem:

$C^2 = A^2 + B^2$

We can treat the side length as the hypotenuse $C$ , the radius as the base $A$ , and solve for height $B$ . Set the expression up like this:

$C^2 = A^2 + B^2\\24^2 = 9^2 + B^2\\B^2 = 24^2 - 9^2\\B = \sqrt{24^2 - 9^2}\\B = \sqrt{576 - 81}\\B = \sqrt{495}\\B \approx 22.25$

Now we can plug into our original formula:

$A = \pi r(r + \sqrt{h^2+r^2})\\A = \pi 9(9+\sqrt{\sqrt{495}^2+9^2}\\A = \pi 9(9+\sqrt{495 + 81}\\A = \pi 9(9+\sqrt{576})\\A = \pi 9(9 + 24)\\A = \pi 9(33)\\A = 297\pi$