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pantera1 [17]
3 years ago
14

In a random group of 23 people, what is the chance in percent that two people have the same birthday ?

Mathematics
2 answers:
yawa3891 [41]3 years ago
3 0

Answer: 50%

Step-by-step explanation:

Don't believe it's true? You can test it and see mathematical probability in action! The birthday paradox, also known as the birthday problem, states that in a random group of 23 people, there is about a 50 percent chance that two people have the same birthday.

ivanzaharov [21]3 years ago
3 0
50%



Because there around 7.594 billion people so to have 23 people in a group together it is 50% that 2 people with have the same birthday
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How many weeks will it take Justin to save $133 if he saves $9.50/wk? Derive a complete equation to model the problem. Use w to
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You can get 4 value meals for 21.88 at the restaurant how much is each value meal?
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Read 2 more answers
A 95% confidence interval for the population proportion of professional tennis players who earn more than 2 million dollars a ye
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Answer:

e. 545

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

The estimate is the mean of the two bounds. So \pi = \frac{0.82+0.88}{2} = 0.85

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

L = \pi - z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, L = 0.82. So

0.82 = 0.85 - 1.96\sqrt{\frac{0.85*0.15}{n}}

1.96\sqrt{\frac{0.85*0.15}{n}} = 0.03

0.03\sqrt{n} = 1.96\sqrt{0.85*0.15}

\sqrt{n} = \frac{1.96\sqrt{0.85*0.15}}{0.03}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.85*0.15}}{0.03})^{2}

n = 544.23

So the correct answer is:

e. 545

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