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2 years ago

Find the Factor of 20

Mathematics

2 answers:

Inga [223]2 years ago

8 0

Answer:

1,2,4,5,10,20

Step-by-step explanation:

All of these WHOLE numbers can be multiplied with another number in the list to equal 20

slega [8]2 years ago

7 0

Answer:

1, 2, 4, 5, 10, 20

these are the factors

1×20= 20

2×10=20

4×5=20

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Mary's four friends have 1/3 of a pound of jelly bellies. They want to put them all together, how much candy do they have ?

Ne4ueva [31]

1 1/3 pounds of jelly babies.

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4 years ago

Mrs. Lay's Instagram followers went from 40 to 72. What was the percent increase?

anastassius [24]

Answer:

The percentage increase when Mrs.Lay’s instagram followers went from 40 to 72 is 80%

Solution:

The percentage increase can be found out by dividing change in value by initial value. This is given as,

$\bold{\text { percentage increase } = \frac{( \text {final count-initial count} }{\text {initial count}} \times 100}$

From question, we get

Initial count of Mrs.Lay = 40

Final value of Mrs.Lay = 72

So percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is

$\text { percentage increase }=\frac{72-40}{40} \times 100$ $= \frac{32}{40} \times 100$

$=\frac{4}{5} \times 100$

= 80

Hence percentage increase when Mrs Lay’s Instagram followers went from 40 to 72 is 80%.

4 0

3 years ago

On day 1, Perry shipped packages and tracked their weight to the nearest kilogram. The packages weighed 1, 8, 1, 12, 1, 11, 7, a

natta225 [31]

Answer:

1.5kg

Step-by-step explanation:

The mean for the packages on day 1 will be:

= (1 + 8 + 1 + 12 + 1 + 11 + 7 + 6)/8

= 47/8

= 5.875

The mean for day 2 will be:

= (47 + 12)/8

= 59/8

= 7.375

The increase in mean:

= 7.375 - 5.875

= 1.5

6 0

2 years ago

-20 2 -6 -18 4 -4 put them from least to greatest

dedylja [7]

-20 -18 -6 -4 2 4 this is the answer

6 0

3 years ago

Read 2 more answers

Scores from an exam are normally distributed with a mean of 85 and a standard deviation of 5. Suppose 188 students take the exam

charle [14.2K]

The mean is $\mu=85$ and standard deviation is $\sigma=5$ . Then the variable $X\sim N(85,5)$ .

Use substitution $Z=\dfrac{X-\mu}{\sigma}=\dfrac{X-85}{5}$ , then the variable $Z\sim N(0,1)$ .

The probability $Pr(X>80)$ can be calculated in the following way:

for X=80, $Z=\dfrac{80-85}{5} =-1$ and $Pr(X>80)=Pr(Z>-1)$ . From the diagram $Pr(Z>-1)=0.34+0.34+0.135+0.025=0.84$ .

Conclusion: if 188 students take the exam, then 188·0.84=157.92 (157) would receive a score above 80

4 0

4 years ago

Read 2 more answers