A given line has the equation 3x-5y=20 . Which of the following equations represents the line perpendicular to the given line an
d passes through the point (-6,4) ?
1 answer:
Answer:
y= -5/3 x - 6
Step-by-step explanation:
3x-5y=20
-5y=20-3x
y= (3/5)x - 5
3/5 is the slope
a perpendicular line's slope is the opposite reciprocal
-5/3 = m
y-y1=m(x-x1)
(-6, 4) = (x1, y1)
plug in the values
y-4= -(5/3) (x+6)
y-4= -5/3 x - 10
y= -5/3 x - 6
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