Question

A given line has the equation 3x-5y=20 . Which of the following equations represents the line perpendicular to the given line and passes through the point (-6,4) ?

Answer 1

Answer:

y= -5/3 x - 6

Step-by-step explanation:

3x-5y=20

-5y=20-3x

y= (3/5)x - 5

3/5 is the slope

a perpendicular line's slope is the opposite reciprocal

-5/3 = m

y-y1=m(x-x1)

(-6, 4) = (x1, y1)

plug in the values

y-4= -(5/3) (x+6)

y-4= -5/3 x - 10

y= -5/3 x - 6