we have
we know that
<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms
p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.
So
in this problem
the constant term is equal to 
and the first monomial is equal to 
-----> coefficient is 
So
possible values of p are 
possible values of q are 
therefore
<u>the answer is</u>
The all potential rational roots of f(x) are
(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
,(+/-)
Answer: 63/16 = 3 1/16 or 7 if your divide it
Step-by-step explanation:
Answer: 5^10
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
Top line: y = (2/3)x + 2
Bottom line: y = (2/3)x -1
Discussion:
The graph provided is hard to read but I did the best I could.
The top line appears to pass through the points (0,2) and (-3,0)
For this line
m = change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>
2 = (2/3) 0 + b => b = 2
Therefore y = (2/3)x + 2
The bottom line appears to pass through the points (0,-1) and (3,1)
For this line
m = change y /change x = (1-(-1)) /(3-0) = +2/-3. So
y = mx + b => y = (2/3) x+ b. As the line passes through (0,-1) set x = 0, y= -1 in y = (2/3)x + b =>
-1 = (2/3) 0 + b => b = -1
Therefore y = (2/3)x + -1
Thank you,
MrB
4/15=x/75
4*75=15*x
300=15x
x=300/15
x=20
