Domain = x
range = y
so like in (4,1) The four is the domain and the range is 1
Step-by-step explanation:
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Answer:
Correct answer: (x-√2)² + (y-√5)² = 3
Step-by-step explanation:
Given data: Center (x,y) = (√2,√5) and r = √3
The canonical or cartesian form of the equation of the circle is:
( x-p )² + ( y-q )² = r²
Where p is the x coordinate of the center, q is the y coordinate of the center and r is the radius of the circle.
God is with you!!!
Answer:
Range [-2,2]
Cosine value varies from -1 to 1, hence -2cos 3x can vary from +2 to -2. The range of the given function , in interval notation, would thus be [-2,2]. In set builder notation it can be expressed as
{y∈R∣−2≤y≤2 }
It most likely might be wrong though so sorry for that.
x= -4 and x=8
f(x) =6║x-2║+3
39= 6║x-2║+3
36=6║x-2║
6=║x-2║
-(x-2)=6
-x+2=6
x=-4
x-2=6
x=8