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2 years ago

Please help thank you! Solve for x and y

Mathematics

2 answers:

Mademuasel [1]2 years ago

6 0

Answer:

Step-by-step explanation:

All 4 sides are equal. (They are marked that way).

8x = 5x + 6 Subtract 5x from both sides

8x - 5x = 5x - 5x + 6 Combine

3x = 6 Divide by 3

3x/3 = 6/3

x = 2

Consecutive angles of a rhombus are supplementary

97 + 12y - 1 = 180 Combine

96 + 12y = 180 Subtract 86 from both sides

12y = 180 - 96

12y = 84 Divide by 12

y = 84/12

y = 7

solong [7]2 years ago

4 0

Answer:

x = 2

y = 7

I aced this lesson in 6th grade.

Step-by-step explanation:

hope this helps. . . <3

good luck! uωu

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99 X 99 X 99 / 9 - 99 /99 PLEASE EXPLAIN ;)

charle [14.2K]

Answer:

107810

Step-by-step explanation:

You can use the order of operations! So we start with 99^3/9. That is 99^2*11. So now let’s do 99/99, it’s 1. So 99^2*11 is 107811, so the answer is 107810.

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3 years ago

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What is the unit rate of 128 dog food for 16 dogs

Sauron [17]

Answer:

128 ÷ 16 = 8

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3 years ago

What is the simplify ratio 40:28

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2 years ago

David is watching maria and alma race electric trains around track. Maria train can go around the track in 10 seconds. Almas tra

Nady [450]

Answer:

60 seconds.

Step-by-step explanation:

We have been given that Maria train can go around the track in 10 seconds. Alma train can go around the track in 12 seconds.

To find the number of seconds after which both trains will cross the finish line together the first time we will find LCM of 10 and 12. LCM will give us the smallest positive integer that is divisible by both 10 and 12.

Multiples of 10 are: 10, 20, 30, 40, 50, 60, 70,...

Multiples of 12 are: 12, 24, 36, 48, 60, 72, 84,..

We can see that least common multiple of 10 and 12 is 60, therefore, it will take 60 seconds for both trains to cross the finish line together the first time.

6 0

2 years ago

When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will

PtichkaEL [24]

Answer:

The correct answer is 9 m per $second^{2}$

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per $second^{2}$

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x m per $second^{2}$ .

∴ 54 = m × x

⇒ x = $\frac{54}{6}$ = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per $second^{2}$ .

6 0

3 years ago