Question

Help with this? Anyone know how to do it? It’s due in the morning

Answer 1

• H=13
• P=5

Using pythagorean theorem

$\\ \sf\longmapsto B^2=H^2-P^2$

$\\ \sf\longmapsto x^2=13^2-5^2$

$\\ \sf\longmapsto x^2=169-25$

$\\ \sf\longmapsto x^2=144$

$\\ \sf\longmapsto x=\sqrt{144}$

$\\ \sf\longmapsto x=12$

Answer 2

Answer:

x = 12

Step-by-step explanation:

→ State Pythagoras theorem

a² + b² = c²

→ Rearrange to make b the subject

b² = c² - a²

→ Square root everything

b = √c² - a²

→ Substitute in the numbers

b = √13² - 5²

→ Simplify

b = 12