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vekshin1
2 years ago
10

Review the graph of complex number z.

Mathematics
2 answers:
STALIN [3.7K]2 years ago
8 0

Answer:

<h2>√10</h2>

Step-by-step explanation:

\text {modulus of z } = =\sqrt{\left( -3\right)^{2}  +\left( 1\right)^{2}  } =\sqrt{9+1} =\sqrt{10}

Dmitriy789 [7]2 years ago
4 0

Answer:

square root of 10

Step-by-step explanation:

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What is 4x4x4x5x5 using index notation
sdas [7]

Answer: 4³ × 5²

Step-by-step explanation:

Index Notation:

This is a short way of writing a number being multiplied by itself.

The base is the number itself and the power is the times the number is multiplied by itself.

With this we can now write the above multiplication in index notation.

we do it as follows : 4³ × 5²

7 0
3 years ago
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Which of the following appear in the diagram below?
Ostrovityanka [42]
the 2 answers are AB and DE
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Gina rented shoes for 2.75 dollars she then bowled three games (2.50 dollars) and then brought nachos for 1.75.she used a coupon
Musya8 [376]

If each game was 2.5 dollars then you would do 2.75 + 3.75 + 1.75 and get 8.25 dollars.

8 0
3 years ago
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Answer the question
Gekata [30.6K]

Answer:

Step-by-step explanation:

(-v² - 3v -8)(3v² + 6v + 3) = -v²*(3v² + 6v + 3) -3v*(3v² + 6v + 3) -8*(3v² + 6v + 3)

= -3v⁴ - 6v³ - 3v² -9v³ - 18v² - 9v - 24v² - 48v - 24

{bring the like terms together}

= -3v⁴ - 6v³ - 9v³ -3v² -18v² -24v²  - 9v - 48v - 24

= -3v⁴ - 15v³ - 45v² - 57v - 24

HINT:

-v²*(3v² + 6v + 3) = -v²*3v² + (-v²)*6v + (-v²)*3

                           = -3v²⁺² - 6v²⁺¹ - 3v²

-3v*(3v² + 6v + 3) = -3v*3v² + 6v*(-3v) + 3*(-3v)

                            = -9v¹⁺² - 18v¹⁺¹ - 9v

                            = -3v³ - 18v² - 9v

                          = -3v⁴ - 6v³ - 3v²

3 0
3 years ago
Does the system have no solution?​
kvv77 [185]

Answer:

\mathrm{A)\:}-6

Step-by-step explanation:

Notice that in the second equation, the coefficient of y is 2 times greater than in the first. Therefore, by making the coefficient of x in the second equation 2 times greater than in the first, it's impossible to only isolate one variable.

Therefore, when a=-3\cdot 2=\fbox{-6}, there are no solutions to this system.

6 0
3 years ago
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