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miss Akunina [59]
3 years ago
8

What are the answers to y=4x+1?

Mathematics
2 answers:
velikii [3]3 years ago
8 0
X = -1/4

Move the 1 to the other side then divide by 4 on both sides
Maurinko [17]3 years ago
4 0

Answer:

x intercept is (-1/4,0) or y intercept (0,1) and you can also enter the problem on mathaway to get your answer hopefully this helps.

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Gambler is deciding whether or not to take a bet. she must pay $40 to take the bet, but if she wins, she willprofit$225.theproba
Vesnalui [34]
Expected value of the bet is
the sum of the products of value of outcome and its probability,
less the amount paid to place the bet.

Outcomes value probability
win            225    1/4
lose               0    3/4
cost of bet = 40

So expected value of bet
E[X]=225*(1/4)+0*(3/4)-40
=56.25-40
=16.25

This means that in the long run, gambler will win, since the expected value is positive.  (does NOT mean she will win in the next bet!)
3 0
4 years ago
An elevator at a department store must carry fewer than 17 people at a time. An elevator operator is present in the elevator at
natulia [17]
I'd say it's x + 1 < 17.
Because the operator should be included as a person as well.
8 0
3 years ago
Read 2 more answers
Can someone help me with this, i don’t really understand it
AlexFokin [52]

Answer:

vertical angle s

Step-by-step explanation:

cause the form a 180º angel

5 0
3 years ago
Which expression is equivalent to (7x−5)−(3x−2)?
Alchen [17]

Answer:

D. 4x-3

Step-by-step explanation:

First you subtract the 7x and 3x to get 4x.

Then you subtract the -5 and the -2 to get -3

Therfore, your answer is D

4 0
3 years ago
What situations would solve by graphing be your preferred choice? Give an example.
Damm [24]

Answer:

1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means

Example;

y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3

2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations

2x + 6y = 16

x + y = 6

We can substitute the value of x = 6 - y, into the first equation and solve from there

3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16

Multiplying the second equation by 2 and subtracting it from the first equation as follows

2·x + 6·y - 2×(x + y) = 23 - 2 × 16

2·x - 2·x + 6·y - 2·y = 23 - 32

0 + 4·y = -9

4) An example of a linear system that can be solved by all three methods is given as follows;

2·x + 6·y = 23

x + y = 16

Step-by-step explanation:

4 0
4 years ago
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