I hope this helps you
P=q/2+9
Use this formula...
(-4 + 8) / 2 , (8 + (-4)) / 2
From there you get...
4 / 2 , 4 / 2
Simplify and you get
(2 , 2)
Answer:
-2x
Step-by-step explanation:
Graph
y > −2x + 3
Use the slope-intercept form to find the slope and y-intercept.
The slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
y = mx + b
Find the values of m and b using the form y = mx + b. m = −2
b = 3
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −2
intercept: (0, 3)
Graph a dashed line, then shade the area above the boundary line since y is greater than
−2x + 3.
y > −2x + 3
Answer:
50°
Step-by-step explanation:
As usual, the diagram is not drawn to scale.
The chord divides the circle into two arcs that have a sum of 360°. If we let "a" represent the measure of the smaller arc, then we have ...
a + (a+160°) = 360°
2a = 200° . . . . . . . . . . . subtract 160°
a = 100°
The measure of the angle at A is 1/2 the measure of the subtended arc:
acute ∠A = a/2 = (1/2)·100° = 50°
_____
<em>Comment on this geometry</em>
Consider a different inscribed angle, one with vertex V on the circle and subtending the same short arc subtended by chord AB. Then you know that the angle at V is half the measure of arc AB. This is still true as point V approaches (and becomes) point A on the circle. When V becomes A, segment VA becomes tangent line <em>l</em>, and you have the geometry shown here.
Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
