Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
Answer:
The correct answer is D) 243
Step-by-step explanation:
1 is the closest to 0 on the number line. Hope this helps!!!!!!!!
Answer:
Option D is the correct answer.
Step-by-step explanation:
Initial height = 4 feet
Given that the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.
Let the rate of growing each year be g.
After 6 years height of tree = 4 + 6g
After 4 years height of tree = 4 + 4g
At the end of the 6th year, the tree was 1/5th taller than it was at the end of the 4th year.
That is

Option D is the correct answer.
The answer is C to the question