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kykrilka [37]
2 years ago
7

In a shop, two kinds of candies A and B were sold at $2 each and $5 each respectively. Tammy paid at least $75 for 20 candies A

and B in the shop. Find the maximum number of candy A Tammy bought.
Mathematics
1 answer:
olga55 [171]2 years ago
6 0

Answer:

Exact answer not possible:  See below.

Step-by-step explanation:

The total that Tammy would pay is the sum of 2A and 5B, where A and B are the number of candies costing $2 and $5, respectively.  Therefore:  

2A + 2B = Total Spent

We are told Tammy spent <u>at least</u> $75, which can be written as "Total Spent > $75."

The equation becomes 2A + 5B > 75

Rearranging:  

2A + 5B > 75

2A  > 75 - 5B

A  > (75 - 5B)/2

To find the maximum of the candy A bought, one can try different values of A and B that result in a total of at least $75.  If the amount spent were $75 exactly, a solution would be 35 A (for $70), leaving $5 for 1 candy B.  But we don't know the exact amount.  The problems states "at least $75."  As far as we know, Tammy may have spent $105, $405, $1,005, or even $4,005 (200 A and 1 B).  One cannot pick a maximum simply since the maximum spent is not defined.  The next possible value above $75 would be $77, which represents 36 A and 1 B candies.

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   |           |         |        |        |       |        |

--------------------------------------------------------

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