Aisha just took a math test consisting of 20 total questions (all worth the same

Mathematics

1 answer:

garri49 [273]2 years ago

7 0

Answer: 3

Explanation:

She wants to get 70%, so we need to solve

x/20 = 70/100

Doing so gets us

100x = 20*70

100x = 1400

x = 1400/100

x = 14

She needs to have 14 questions correct, out of 20, to get a score of 70%

14/20 = 0.70 = 70%

She needs to get 14-11 = 3 more correct questions.

You might be interested in

Round 5,939576 to the nearest hundred thousand

TiliK225 [7]

Answer:

5,939,576.000

Step-by-step explanation:

none added explanation, hoped it help!

7 0

4 years ago

Read 2 more answers

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$