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Nuetrik [128]
3 years ago
11

Describe the end behavior of the following graphs

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

Step-by-step explanation:

We have to see what happens at each graph at the “end” of x axis This means look both to the left and right of the x axis

1) when x approaches -oo, f(x)approaches -oo. When x approaches +oo, f(x) approaches +oo

2) when x approaches -oo, f(x) approaches +oo. When x approaches +oo, f(x) approaches +oo

3) when x approaches -oo, f(x) approaches -oo. When x approaches +oo, f(x) approaches -oo

4) when x approaches -oo, f(x) approaches -oo. When x approaches +oo, f(x) approaches +oo

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List the sets that -6 belongs to: whole numbers, integers, rational numbers, irrational numbers, and real numbers.
goldfiish [28.3K]

Answer:

Whole Number : 6

Integers: -6 and 6

Rational Number: -6.0 and -6/1

Irrational Number: -Infinity  or  -0


8 0
4 years ago
1. You are planning a pizza party. You can purchase small cheese pizzas for $5.50 each
baherus [9]

Answer:

x+y=8

5.50x+7y=51.50

Step-by-step explanation:

3 0
3 years ago
IF YOU CAN HELP! That would be great!
iVinArrow [24]

5x^2 - 6x^2 = - x^2 so its either c or d.

and + 9x - )-3x) = 9x + 3x = + 12x

so the answer s C.

7 0
3 years ago
Read 2 more answers
Simplify. 16 – 7 – (–4) + 12 A. –7 B. 17 C. 25 D. 39
alexandr402 [8]
1)  16-7+4+12
       =25
so the answer is C
hope it helps
6 0
3 years ago
Levi invested $5,300 in an account paying an interest rate of 2.4% compounded daily. Assuming no deposits or withdrawals are mad
suter [353]

Answer: $6,120.86

Step-by-step explanation:

Formula to calculate the accumulated amount in n years (compounded daily)  is given by :-

A=P(1+\dfrac{r}{365})^{365\times n}

P= Initial amount

r= Rate of interest ( in decimal)

As per given , we ahve

P= $5300

r= 2.4%=0.024

n= 6 years

Put these values in formula , we get

A=5300(1+\dfrac{0.024}{365})^{365\times6}\\\Rightarrow\ A=5300(1.00006575342)^{2190}\\\Rightarrow\ A=6120.85673631\approx6120.86

Hence, there would be $6,120.86 in the account after 6 years.

5 0
4 years ago
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