Question

Three vertices of parallelogram JKLM are J(1, 4), K(5, 3), and L(6,−3). Find the coordinates of vertex M.

Answer 1

Answer:

coordinates of vertex M is (x, y) = (2, -2)

Step-by-step explanation:

Since JKLM is a  parallelogram, this implies that JK parallel to LM and KL parallel to JM. This means that

Slope of JK = slope of LM

$\frac{3-4}{5-1} =\frac{-3-y}{6-x} \\y=-\frac{1}{4}x-\frac{3}{2} ....(i)$

And

Slope of KL = slope of JM

$\frac{3-\left(-3\right)}{5-6}=\frac{4-y}{1-x}\\y=10-6x...(ii)$

From equation (i) and (ii) we get

$-\frac{1}{4}x-\frac{3}{2} =10-6x$

$-\frac{23x}{4}=-\frac{23}{2}$

$-23x=-46$

$x=2$

Put the value of x in equation (ii) we get

$y=10-6(2)\\y=-2$

So, the coordinates of vertex M is (x, y) = (2, -2).