First, you should solve for

, which equals

. Now, solve the integral of

=

, to get that

. You can check this by taking the integral of what you got. Now by the Fundamental Theorem
![\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8](https://tex.z-dn.net/?f=%20%5Cint%5Climits%5E2_0%20%7B4x%7D%20%5C%2C%20dx%3D%5B2x%5E2%5D%20%5E%7B2%7D_%7B0%7D%3D2%282%29%5E%7B2%7D-2%280%29%5E2%3D8)
.
This should be the answer to your question, if I understood what you were asking correctly.
Answer:

Step-by-step explanation:





C=dπ and r+r=d so 3+3=6 and 6π≈18.84 so the circumference would be 18.84
The answer is one and five elevenths, or: 1 5/11
this is because 140/2.5 is 56 and 300/5.5 is 54 6/11.
56 - 54 6/11= 1 5/11
Well it depends on what the model is but if it's an IRA or whatever so if you make your own model that's easy