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Rus_ich [418]
3 years ago
10

A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be use

d to find the cost of the gum 20 years ago?
Mathematics
2 answers:
Aleks [24]3 years ago
6 0
The answer to your question is: .75 = 3x - .03

How to solve it:

x = the cost of a pack of gum twenty years ago

.75 =  3x - .03
+ .03      + .03

.78 = 3x
 / 3    / 3         

.26 = x

If a pack of gum now costs 75 cents, which is 3 cents less than three times what a pack would have cost 20 years ago, then a pack of gum would have cost 26 cents. 
Talja [164]3 years ago
6 0

Answer:

C) 3x - 0.03 = 0.75

Step-by-step explanation:

i got it right

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DENIUS [597]
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This means -3 would be your x and -4 would be your y.

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In other words, it would be (-3 - -4) / (4 - -3) = 1/7 which is your slope (m).

Now plug that in for m to get the b variable.

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7 0
3 years ago
Bianca has a total of $0.25 she has some nickels and pennies how many different combinations of nickels and pennies could Bianca
grandymaker [24]
4 nickels and 5 pennies. 
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4 0
3 years ago
PLeAsE sEnD hElP !!!!!!!!!!!!!!!!
Luba_88 [7]

Answer:

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Step-by-step explanation:

If DG, EG and FG are perpendicular bisectors of the sides of triangle ABC, then point G is the circumcenter of the triangle ABC and

BG = AG = CG as radii of the circumcirle.

Consider right triangle BEG. By the Pythagorean theorem,

BG^2=EG^2+BE^2\\ \\BG^2=4^2+3^2\\ \\BG^2 =16+9\\ \\BG^2=25\\ \\BG=5\ units

This gives us that

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