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vampirchik [111]
2 years ago
9

Graph the line through (1,1) with slope 3/2​

Mathematics
1 answer:
Dafna11 [192]2 years ago
5 0

Answer:

y = (3/2)x - (1/2)

Step-by-step explanation:

The general structure of a line in slope-intercept form is:

y = mx + b

In this form, "m" represents the slope and "b" represents the y-intercept. You have been given the value of "m" (3/2). To find the value of "b", you should plug "m" into the equation in addition to the "x" and "y" values from the given point (1,1)

(1,1) ----> x = 1, y = 1

m = 3/2

y = mx + b                                <----- Slope-intercept form

y = (3/2)x + b                            <----- Plug (3/2) into "m"

1 = (3/2)(1) + b                           <----- Plug values into "x" and "y" from point

1 = (3/2) + b                              <----- Multiply (3/2) and 1

(2/2) = (3/2) + b                        <----- Change 1 into common denominator

(-1/2) = b                                  <----- Subtract (3/2) from both sides

Because you now have values for both variables, you can construct your final equation.

y = (3/2)x - (1/2)

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