HELP ME PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Which lines are parallel to 8x + 4y = 5? Select all that apply.

Dvinal [7]

Answer:

A , B , C

Step-by-step explanation:

1) find the slope of the given line

slope = (-a/b) = (-8/4) = -2

two parallel lines have the same slope

A : correct

B : (-a/b) = -16/8 = -2 (correct)

C : correct

D : wrong (2 is different from -2)

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME WITH THIS ONE ASAP PLEASE AND THANK YOU thanks in advance

Andreyy89

Answer:

ok so 10 times 4 equals 40 and then 40 times six equals 240 but I don't know what standard notation is

7 0

3 years ago

Read 2 more answers

Please help me with 8, 9, and 10 thanks! Show work too

Harrizon [31]

In 8, 9, 10, all the triangles are similar, meaning corresponding sides have the same ratio.

8. hypotenuse / (short side) = 25/x = x/9
x² = 25*9 = 5²×3²
x = √(5²×3²) = 5*3 = 15

9. (long side) / (short side) = x/7 = 9/x
x² = 7*9
x = √(9*7) = 3√7

10. (short side) / (long side) = x/48 = 48/64
x = 48²/64 = 36

3 0

3 years ago

Can someone explain how to do this and add the formula please

lisabon 2012 [21]

Answer:

5 is 35 and 6 is 50

Step-by-step explanation:

To solve 5, you need to know how many degrees is the line, which is 180 because lines are 180 degrees. You then subtract 110 from 180 which equals to 70. What you have left now is 2k. A number times 2 will equal to 70, so k=35.

For 6, if you ever see two lines intersecting each other, it means that it is 360 degrees. We already have one angle, which is 120. The other angle is d+70 degrees, and any angle that is reflecting the other angle will have the same value. So, d equals 50

(sorry if you still can't understand it I'm not good at English

6 0

2 years ago

You work at a pioneer historical site. On this site you have handcarts. One cart has a handle that connects to the center of the

Gelneren [198K]

Answer:

a) see below

b) radius = 16.4 in (1 d.p.)

c) 18°. Yes contents will remain. No, handle will not rest on the ground.

d) Yes contents would spill. Max height of handle = 32.8 in (1 d.p.)

Step-by-step explanation:

Part a

A chord is a line segment with endpoints on the circumference of the circle.

The diameter is a chord that passes through the center of a circle.

Therefore, the spokes passing through the center of the wheel are congruent chords.

The spokes on the wheel represent the radii of the circle. Spokes on a wheel are usually evenly spaced, therefore the congruent central angles are the angles formed when two spokes meet at the center of the wheel.

Part b

The tangent of a circle is always perpendicular to the radius.

The tangent to the wheel touches the wheel at point B on the diagram. The radius is at a right angle to this tangent. Therefore, we can model this as a right triangle and use the tan trigonometric ratio to calculate the radius of the wheel (see attached diagram 1).

$\sf \tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle

Given:

$\theta$ = 20°
O = radius (r)
A = 45 in

Substituting the given values into the tan trig ratio:

$\implies \sf \tan(20^{\circ})=\dfrac{r}{45}$

$\implies \sf r=45\tan(20^{\circ})$

$\implies \sf r=16.37866054...$

Therefore, the radius is 16.4 in (1 d.p.).

Part c

The measure of an angle formed by a secant and a tangent from a point outside the circle is half the difference of the measures of the intercepted arcs.

If the measure of the arc AB was changed to 72°, then the other intercepted arc would be 180° - 72° = 108° (since AC is the diameter).

$\implies \sf new\: angle=\dfrac{108^{\circ}-72^{\circ}}{2}=18^{\circ}$

As the handle of the cart needs to be no more than 20° with the ground for the contents not to spill out, the contents will remain in the handcart at an angle of 18°.

The handle will not rest of the ground (see attached diagram 2).

Part d

This can be modeled as a right triangle (see diagram 3), with:

height = (48 - r) in
hypotenuse ≈ 48 in

Use the sin trig ratio to find the angle the handle makes with the horizontal:

$\implies \sf \sin (\theta)=\dfrac{O}{H}$

$\implies \sf \sin (\theta)=\dfrac{48-r}{48}$

$\implies \sf \sin (\theta)=\dfrac{48-45\tan(20^{\circ})}{48}$

$\implies \theta = 41.2^{\circ}\:\sf(1\:d.p.)$

As 41.2° > 20° the contents will spill out the back.

To find the maximum height of the handle from the ground before the contents start spilling out, find the height from center of the wheel (setting the angle to its maximum of 20°):

$\implies \sin(20^{\circ})=\dfrac{h}{48}$

$\implies h=48\sin(20^{\circ})$

Then add it to the radius:

$\implies \sf max\:height=48\sin(20^{\circ})+45\tan(20^{\circ})=32.8\:in\:(1\:d.p.)$

(see diagram 4)

------------------------------------------------------------------------------------------

Circle Theorem vocabulary

Secant: a straight line that intersects a circle at two points.

Arc: the curve between two points on the circumference of a circle

Intercepted arc: the curve between the two points where two chords or line segments (that meet at one point on the other side of the circle) intercept the circumference of a circle.

Tangent: a straight line that touches a circle at only one point.

7 0

2 years ago

HELP ME PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!​

HELP ME PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!