Answer:
f(g(x)) = 15x³ - 5
Step-by-step explanation:
how confusingly described.
let me try and summarize what I understood :
f(x) = 3x² - 5
money earned when baking x cookies.
g(x) = sqrt(5x³)
the amount of cookies baked in x hours.
f(g(x)) now calculates how much money she earns when baking for x hours.
it is basically very simple : instead of f(x) we have f(g(x)), so g(x) is used as argument/variable in f instead of just plain x.
therefore,
f(g(x)) = 3×(sqrt(5x³))² - 5
with x now representing the baking hours, but f(...) calculating the overall money earned, by implicitly (!) calculating the amount of cookies baked in that time and taking that result automatically to calculate the earned money.
let's simplify this a little bit more.
f(g(x)) = 3×(sqrt(5x³))² - 5 = 3×(5x³) - 5 = 15x³ - 5
Part A. Your model is as good as any. It is hard to tell if the label needs to include the descriptor (length = 12 ft, for example). Certainly your model is sufficient for Part B.
Part B. The total area is the sum of the areas of each of the 6 faces of the box. Opposite faces are the same area, so you have
A = 2(LW +WD +LD) = 2(LW +D(L +W))
Subsituting the given dimensions, you get
A = 2((12 ft)(6 ft) +(3 ft)(12 ft +6 ft))
A = 2(72 ft² +(3 ft)(18 ft))
A = 2(72 ft² +54 ft²) = 252 ft²
The least amount of paper required to cover the box is 252 ft².
a right angle is 90°, or 1/4 of a circle.
3/5 * 1/4 = 3/20
radian measure is the length of the circumference of this part of the circle.
a full circumference of a circle would be 2*pi*r, also expressed as 2 rad * r
now let's multiply the full thing with the 3/20 from earlier to just get the desired fraction:
6/20 rad * r
<u>= 3/10 rad * r</u>
of course a solution in cm or inch still depends on the radius here, wich could be just plugged in at will
Answer:
first option
Step-by-step explanation:
Using the rule of exponents
= 
then
= 
= 
Solve each system by substitution. Check your solution. Writing How do you know that substitution gives the answer to a system of equations? ... You Would solve the second equationfor y and then substitute back into the first equation.
