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3 years ago

The darkest part of the moon's shadow is?

1 answer:

5 0

The umbra is the darkest part of the moons shadow.
From within the umbra, the Sun is completely blocked by the Moon as in the case of a total eclipse.

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The increase in trade and commerce during the middle ages resulted in

Keith_Richards [23]

The increase in trade and commerce during the middle ages resulted in the increase of the growth of towns and cities.

5 0

2 years ago

Why are certain areas of Africa at an extreme risk of becoming failed states?

garik1379 [7]

Answer:

In Africa not all places are able to enforce laws or provide basic goods and services to its citizens because of high crime rates, political corruption, ect.

Explanation:

7 0

3 years ago

What is the value of X6? Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

2 years ago

Four examples of renewable resources are featured in the Energy Conversions Gizmo. These resources are produced all the time, so

storchak [24]

Answer:

Solar energy.

Wind energy.

Geothermal energy.

Hydropower.

Explanation:

Solar energy, Wind energy, Geothermal energy and Hydropower are the renewable resources from which energy is produced and they will never run out because they are produce by nature in large quantity. Solar energy is the energy produced from the sun, Wind energy is the energy produced from the speed of wind, Geothermal energy is the energy produced from the heat of earth and Hydropower is the energy produced due to falling water from higher altitude.

6 0

2 years ago

The process that returns water to the atmosphere from the surface of lakes and oceans is called

LUCKY_DIMON [66]

It's called evaporation.

7 0

2 years ago