<h3>
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We know that, Two angles are said to be complementary, if the sum of their measures is 90°.
<u>According to the Question</u>,
⇒ ∠ABD + ∠DBC = 90°
⇒ (2x + 30)° + (3x + 20)° = 90°
⇒ 2x + 30° + 3x + 20° = 90°
⇒ 5x + 50° = 90°
⇒ 5x = 90° - 50°
⇒ 5x = 40°
⇒ x = 40°/5
⇒ x = 8
<u>So</u>, <u>t</u><u>he measure of each angle will be</u>,
⇒ ∠ABD = (2x + 30)°
= 2 × 8 + 30°
= 16 + 30°
= 46°
⇒ ∠DBC = (3x + 20)°
= 3 × 8 + 30°
= 24 + 30°
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= 54° ▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
Answer: b+95+34=180, b+129=180, 51
Step-by-step explanation:
b+95+34=180 works because the angles add to form a straight angle.
From this, we can obtain b+129=180 by adding the two constants.
Subtracting 129 from both sides, we get b=51.
Answer:
29°
Step-by-step explanation:
151° + a=180°
We know the sum of angles in a straight line is 180°
a= 180°-151°
The sign changed as it changed sides
a= 29°
Child's ticket x=y-5.75
Adult would be found by solving for y.
x=y-5.75
5.75+x=y-5.75+5.75
5.75+x=y
Y=x+5.75
We are given that the sides GH and DE of the triangles are congruent.
Also, we are given that the angles H and E are congruent.
i) if we are given that HI is congruent to EF, then the triangles are congruent, by Side Angle Side postulate.
or
ii) if we are given that angles G and D are congruent, then the triangles are congruent by the Angle Side Angle postulate.