First, assign a variable that you're looking for.
Let x = the larger number
Then x - 1 = the smaller number
The sum of x and x - 2 will equal to 226.
x + x - 1 = 226
2x - 1 = 226
2x = 228
x = 114
So, the smaller number is 112 and the larger number is 114.
Answer:
b^4
Step-by-step explanation:
you would just subtract the variables things
b^10-b^6
subtract 10-6 and keep the b
b^4 iis the answer we are learnng these in school right now
The ordered pair is a solution of x - y = 2 and 3y - x = 8 is (x, y) = (7, 5)
<h3><u>Solution:</u></h3>
Given two equations are:
x - y = 2 and 3y - x = 8
<em><u>To find: orderes pair i.e (x, y)</u></em>
Let us consider:
x - y = 2 ------- eqn 1
3y - x = 8 --------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "x" and "y"</u></em>
On rearranging eqn 2, we get
-x + 3y = 8 ------ eqn 3
Add eqn 1 and eqn 3
x - y = 2
-x + 3y = 8
(+) ---------------
0 + 2y = 10
2y = 10
<h3>y = 5</h3>
Therefore from eqn 1,
x - y = 2
x - 5 = 2
x = 5 + 2 = 7
<h3>x = 7</h3>
Thus the ordered pair to the given equations are (x, y) = (7, 5)
