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2 years ago

5

Jadon has 4 feet of ribbon to decorate pockets. He needs 1/3 foot of ribbon to decorate each pocket. How many pockets will jadon

be able to decorate?.

1 answer:

jolli1 [7]2 years ago

5 0

Answer:

4 feet of ribbon ÷ 1/3 foot riboon = 12 pockets

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Solve for x: 6x + 1 over 4 (4x + 8) > 12

sukhopar [10]

Answer:

A. $x>\frac{10}{7}$ .

Step-by-step explanation:

We have been given an inequality $6x+\frac{1}{4}(4x+8)>12$ . We are asked to solve the given inequality for x.

Using distributive property, we will get:

$6x+\frac{1}{4}*4x+\frac{1}{4}*8>12$

$6x+x+2>12$

$7x+2>12$

Subtract 2 from both sides:

$7x+2-2>12-2$

$7x>10$

Divide both sides by 7:

$\frac{7x}{7}>\frac{10}{7}$

$x>\frac{10}{7}$

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Step-by-step explanation:

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Which values are solutions to StartFraction k minus 3 Over 4 EndFraction >–2? Select two options. k = –10 k = –7 k = –5 k = –

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Nina purchased apples and strawberries. She purchased a total of 9 pounds of fruit and spent a total of $16.35. Strawberries cos

irina [24]

Answer:

4 pounds of strawberries and 5 pounds of apples are bought.

Step-by-step explanation:

Given:

Total number of pounds of fruit = 9 pounds

Total money spent = $16.35

Cost of 1 pound of strawberry = $1.60

Cost of 1 pound of apple = $1.99

Let 'x' pounds of strawberries and 'y' pounds of apples are bought.

So, <u><em>as per question:</em></u>

<em>The sum of the pounds is 9. So,</em>

$x+y=9\\\\y=9-x----1$

Now, total sum of the fruits is equal to the sum of 'x' pounds of strawberries and 'y' pounds of apples. So,

$1.60x+1.99y=16.35----2$

Now, plug in the 'y' value from equation (1) in to equation (2). This gives,

$1.60x+1.99(9-x)=16.35\\\\1.60x+17.91-1.99x=16.35\\\\Combining\ like\ terms, we get:\\\\1.60x-1.99x=16.35-17.91\\\\-0.39x=-1.56\\\\x=\frac{-1.56}{-0.39}=4\ pounds$

Now, from equation 1, we have:

$y=9-4=5\ pounds$

Therefore, 4 pounds of strawberries and 5 pounds of apples are bought.

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