Question

The length of a rectangle is two-fifths of its perimeter. if the width of the rectangle is 35 inches, what is its length in inches?

Answer 1

Width = xlength = 4x Use the formula for the perimeter of a rectangle to solve for x: perimeter = 2(length) + 2(width)50 = 2(4x) + 2(x)50 = 8x + 2x50 = 10x5 = x The width (x) is 5 feet and the length (4x) is 20 feet.

Answer 2

Answer:

Length = 140 inches.

Step-by-step explanation:

Given  : The length of a rectangle is two-fifths of its perimeter. if the width of the rectangle is 35 inches.

To find : what is its length in inches.

Solution : We have given  

Length of rectangle = L.

Perimeter = P.

According to question

Length of a rectangle is two-fifths of its perimeter.

L = $\frac{2}{5} * perimeter$.

L=  $\frac{2}{5} * perimeter$.

Width = 35 inches .

Perimeter = 2 ( length + breadth ) .

Plug the values of length =  $\frac{2}{5} * perimeter$ ; Width = 35 inches .

Perimeter = 2 (  $\frac{2}{5} * perimeter$  + 35).

P =  $\frac{4}{5} * P + 70$ .

On subtracting from both side  by   $\frac{4}{5} * P$ .

P -  $\frac{4}{5} * P$  = 70 .

$\frac{5 P - 4P}{5}$  = 70 .

$\frac{P}{5}$  = 70.

On multiplying both side by 5

P = 70 *5

P = 350 inches .

Now , Plug value of perimeter in Length.

Length =  $\frac{2}{5}* perimeter$.

Length =  $\frac{2}{5}* 350$.

Length = 140 inches.

Therefore, Length = 140 inches.