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tester [92]
3 years ago
12

One of the parking lot lights at a hospital has a motion detector on it, and the equation (x+10)2+(y−8)2=16 describes the bounda

ry within which motion can be sensed. What is the greatest distance, in feet, a person could be from the parking lot light and be detected?
Mathematics
2 answers:
DIA [1.3K]3 years ago
5 0
The correct answer is 4ft

<span>because the radius of that circle </span>
<span>(x+10<span>)^2</span>+(y−8<span>)^2</span>=<span>4^2</span></span>
<span>is  4</span>
Vinil7 [7]3 years ago
5 0

Answer:

The greatest distance covered by the camera is 4 feet.

Step-by-step explanation:

It has been given in the question that one of the parking lot lights at a hospital has a motion detector which covers a boundary described by an equation

(x + 10)²+(y - 8)² = 16 = 4²

Since this equation is in the form of (x - a)² + (y - b)² = r²

It's a standard equation of a circle having center (h, k) and r as the radius.

So 4 feet is the maximum distance which camera can cover.

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Answer

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Step by step explanation

Here we have to use the midpoint formula.

Midpoint = ( \frac{x1 + x2}{2} , \frac{y1 + y2}{2} \\)

Here the point A = (-1, 8) and B = (7, 3)

x1 = -1, y1 = 8, x2 = 7 and y2 = 3

Now plug in these values into the formula.

Midpoint = (\frac{-1 + 7}{2} , \frac{8 + 3}{2}

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Thank you.


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Answer:

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Step-by-step explanation:

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