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Lina20 [59]
2 years ago
6

For f(x) = 4x + 2 and g(x) = x² − 6, find (ƒ+ g)(x).

Mathematics
1 answer:
Orlov [11]2 years ago
3 0

Answer: x² + 4x - 4

Given that:

  • f(x) = 4x + 2
  • g(x) = x² − 6

Solve for (f + g)(x):

  • f(x) + g(x)
  • 4x + 2 + x² − 6
  • x² + 4x - 4
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ICE Princess25 [194]

Answer:

the equation of the perpendicular bisector of segment AB is y = -2x + 7

Step-by-step explanation:

Going from B(-1, 4) to A(3, 6), x increases by 4 and y increases by 2.  Thus, the slope of this line is m = rise / run = 2/4, or 1/2.

Any line perpendicular to the one joining A and B has a slope which is the negative reciprocal of 1/2:  that'd be -2.

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The midpoint of line segment AB is ( --------- , ---------- ), or (1, 5)

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Starting from y = mx + b, we get  5 = -2(1) + b, or 7 = b, and so the equation of the perpendicular bisector of segment AB is

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6 0
3 years ago
I will mark you as a brainlist please explain fully!!
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Answer:

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