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Mkey [24]
3 years ago
13

For argument's sake let's say that the odds of seeing a black cat are 25% every day. You've not seen one for the past three days

. What percent chance is there to see one on the fourth day? Explain your answer. *
Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0
<h2>Answer:</h2><h2>The chance is 100 % since we have not seen it in the past three days.</h2>

Step-by-step explanation:

The odds of seeing a black cat are 25% every day.

It also means that the possibility of seeing  a black cat is once in 4 days, since 25%

Given, we have not seen one black cat in 3 days.

The chance of seeing a black cat on the 4th day = ?

= 100 % since we have not seen it in the past three days.

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Answer:

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Step-by-step explanation:

Use substitution to solve your equation. Plug in y=2x-1 into y=1/2x+4. This makes (2x-1)=1/2x+4. Simplify this to get 3/2x-1=4. Simplify it again to get 3/2x=5. No one likes fractions so multiply both sides by 2 to get 3x=10. Simplify this and get x=10/3. Plus 10/3 into one of the equations. You can pick anyone but I picked y=2x-1. Because you know x=10/3, you put y=2(10/3)-1. Simplify this and get y=20/3-1. Convert 1 into a fraction and get y=20/3-3/3. Simplify this and get y=17/3.

Therefore,

x=10/3 y=17/3

Hoped this helps you

7 0
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