Answer:
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Step-by-step explanation:
For terms to be like terms, they must have exactly the same variables and the same exponents.
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Answer:
Where's the question?
Step-by-step explanation:
Let the measure of side AB be x, then, the measue of side AE is given by

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Now, ABCD is a square of size x, thus the area of square ABCD is given by

Also, AEFG is a square of size

, thus, the area of square AEFG is given by

<span>The sum of the areas of the two squares ABCD and AEFG is given by

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>
Answer:
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