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3 years ago

Grocery store sells tangerines in 2/5 kg bags. A customer bought 4kg of tangerines for a school party. How many bags did he buy

1 answer:

6 0

In order to have 4 kg, he must have 20/5 kg. Each bag is 2/5 kg, so 2/5 times 10 is 20/5 or 4kg. Therefore, he bought 10 bags of tangerines for the school party.

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Evaluate C=2 pi r for r=8 A. C=10 pi B. C=16 pi C. C=28 pi D. C=16

Brrunno [24]

Answer:

If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

4. 9d - 5 = 4 What does d = 5. 6-3w=-27 what does w = 6. -4= q/8-19 what does q =

trapecia [35]

Answer:

4) d = 1

5) w = 11

6) q = 120

Step-by-step explanation:

4) $9d - 5 = 4$

Adding 5 on both the sides ,

$= > 9d - 5 + 5 = 4 + 5$

$= > 9d = 9$

Dividing both the sides by 9 ,

$= > \frac{9d}{9} = \frac{9}{9}$

$= > d = 1$

5) $6 - 3w = - 27$

Substracting 6 from both the sides ,

$6 - 3w - 6 = - 27 - 6$

$= > - 3w = - 33$

Dividing both the sides by -3 ,

$= > \frac{ - 3w}{ - 3} = \frac{ - 33}{ - 3}$

$= > w = 11$

6) $- 4 = \frac{q}{8} - 19$

Adding 19 on both the sides ,

$\frac{q}{8} - 19 + 19 = - 4 + 19$

$= > \frac{q}{8} = 15$

Multiplying both the sides by 8 ,

$= > \frac{q}{8} \times 8 = 15 \times 8$

$= > q = 120$

6 0

3 years ago

A Starbucks coffee shop serves an average of 3500 customers per day, with a standard deviation of 250. What is the probability t

castortr0y [4]

Answer:

$P(3300$

And we can find this probability with this difference:

$P(-0.8$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the amount of cofee shops of a population, and for this case we know the distribution for X is given by:

$X \sim N(3500,250)$