When light moves from one medium to another, it is refracted. If it moves from a medium with refractive index n1 to one with refractive index n2, with an incidence angle to the surface normal of θ1, the refraction angle θ2 can be calculated from Snell's law.
The Snell's law states that the ratio of the sines of the angles of incidence and refraction of a wave (in this case beam/light) are constant when it passes between two given media.

Given that a <span>laser travels from glass to water at an angle of 35° with the normal, </span>
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<span>. If water has an index of refraction of 1.33 and glass has an index of refraction of 1.52, then we have:
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
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If you add 5x to 2x+2 you will get 7x+2. You would set this equation equal to 80, so it would be 7x+2=80. When you solve this you will get 11.1428571429, which can be rounded to 11, 11.1, or 11.14, whichever you prefer.
Answer:
g(0.9) ≈ -2.6
g(1.1) ≈ 0.6
For 1.1 the estimation is a bit too high and for 0.9 it is too low.
Step-by-step explanation:
For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.
For 0.9, we estimate
g(0.9) ≈ 16* (-0.1) -1 = -2.6
g(1.1) ≈ 16* 0.1 -1 = 0.6
Answer:
BD = 12 :)
Step-by-step explanation:
Alright, we'll need the Pythagorean theorem for this!
So, the length of AC is 10. That means the lengths of AD and DC are both half of that, which is 5 :)
DC = 5
We already know that BC = 13, so we can plug in these values into the pythagorean theorem for the right triangle BDC:
BD^2 + DC^2 = BC^2
BD^2 + 5^2 = 13^2
BD^2 + 25 = 169
BD^2 = 169 - 25 = 144
BD = √144 = 12 :)