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Oliga [24]
3 years ago
14

8.0x=x^3+3.0x^2 solve for x

Mathematics
1 answer:
katovenus [111]3 years ago
5 0

First of all, move all terms to the same side:

x^3 + 3x^2 - 8 x = 0

You can factor an x, which means that x = 0 is a solution:

x(x^2+3x-8)

This expression is further factorizable if the quadratic equation has any solution. Using the quadratic formula, we can find that they are

x_{1,2} = -\dfrac{3 \pm \sqrt{41}}{2}

So, we have

x(x^2+3x+8) = 0 = \iff x = 0,\quad x =-\dfrac{3 + \sqrt{41}}{2} ,\quad x =-\dfrac{3 - \sqrt{41}}{2}

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\implies {\blue {\boxed {\boxed {\purple {\sf { f(-9)= 0.48}}}}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

f(x) =  \frac{2x + 3}{4x + 5} \\

For f(-9), put "-9" for every value of "x".

↬f( - 9) =  \frac{2( - 9) + 3}{4( - 9) + 5}\\

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\bold{ \green{ \star{ \red{Mystique35}}}}⋆

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