Answer:
x = 600 m
y = 1200 m
Amax = 720000 m²
Step-by-step explanation:
Let call x the smaller side of the rectangular plot and y the largest ( we assume we have one y side bounded by a river: Then
A(p) Area of the plot x*y
A(p) = x*y
And perimeter of the plot ( to be fenced ) is:
P(p) = 2*x + y = 2400 ⇒ y = 2400 - 2*x
Area of rectangular plot as function of x:
A(x) = x * ( 2400 - 2x )
Taking derivatives on both sides of the equation
A´(x) = ( 2400 - 2x ) + (-2) *x ⇒ A´(x) = ( 2400 - 2x ) - 2x
A´(x) = 0 ⇒ 2400 - 4x = 0 ⇒ 4x = 2400
x = 600 m
And y = 2400 - 2*x
y = 2400 - 1200
y = 1200 m
And the largest enclosed area is Amax = 1200*600
Amax = 720000 m²
Answer:
5
Step-by-step explanation:
5
lol hope helps :D
It should be letter D positive 1
The value of x is 2 and KNL will be 102
The area equation for a rectangle is length times width. And the area equation for a half (or semi) circle is (1/2) times pi (or 3.14) times the radius squared.
So, you have to add the area of the rectangle and semi-circle together.
Rectangle: A = 18*10 = 180 cm^2
Semi-circle: A = (1/2)*3.14*(18/2)^2 = 127.17 cm^2
Add those together to get 307.17cm^2 or choice C.
