Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
D) L=50 W=50
Step-by-step explanation:
Just "plug and chug" these numbers and see which doesn't work.
A is not it, 20+30=50 (then *2 because we need 4 sides not just 2) 50*2=100
B isn't it, 10+40=50*2=100
C ain't it either 49+1=50*2=100
D is the answer 50+50=100*2=200
Answer:
Hi there!
The following answers:
3. 7 c > 3 (1/4) pt 4. 5 gal > 18 qt
5. 45 cm = 450 mm 6. 4.5 km < 5000 m
Step-by-step explanation:
There are 2 cups in one pint.
There are 4 quarts in one gallon.
One kilo meter is 1000 meters.
1 inch = 25 miles so 5inches x 25 = 125 miles
Answer:
a. 28
Step-by-step explanation:
Given:
We need to evaluate given expression to find the value of 'h'.
Solution:
Now first we will apply Subtraction property of equality and subtract both side by 73.18 we get;
Now we will use Division property of equality and divide both side by 2.95 we get;
Hence After evaluating given expression we get the value of 'h' as 28.
