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natka813 [3]
2 years ago
7

le="\sf\large\green{\underbrace{\red{Question*}}}:" alt="\sf\large\green{\underbrace{\red{Question*}}}:" align="absmiddle" class="latex-formula">
\mathbb\blue{SOLVE}
\pink{1. \:  \:  \:  \:  \:  \:  (3 - x)(x + 2) = 0}
\pink{2. \:  \:  \:  \:  \: {(q + 2)}^{2}  - 40}
​
Mathematics
1 answer:
Setler79 [48]2 years ago
5 0

\large{\underline{\underline{\pmb{\sf{\color {red}{Solve:}}}}}}

\sf \red{1. \: (3x - x) (x + 2) = 0}

\sf \red{2. \: (q + 2)^{2} - 40}

\large{\underline{\underline{\pmb{\frak {\color {blue}{Answer:}}}}}}

2.soln:

(q + 2)² - 40

=> (q)² + 2.q.2 + (2)² - 40

=> q² + 4q + 4 - 40

=>q² + 4q - 36

Here, a = 1, b = 4 and c = - 36

By, using Quadratic formula

See the attachment

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