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Andreas93 [3]
3 years ago
8

Fancy Nails charges $28 for a pedicure plus $9 for each treatment. Lara's Nails charges $22 for

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

Answer:

It's B.3

Step-by-step explanation:

Substitution. With the equation Y= 9x+28 and Y= 11x+22, you substitute the x-factor with '3'. Which will give you

Y= 9(3)+28         Y= 11(3)+22

Y= 27+28           Y= 33+22

Y= 55                 Y= 55

slava [35]3 years ago
4 0

Answer:C.4

Step-by-step explanation:

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What is the domain of the function f(x) = x^2 + 5?
Sophie [7]

The domain is R so the first one is correct.

4 0
2 years ago
Luis is taking out a car loan for $5,000. He plans on paying off the car loan in 2 years. At the end of 2 years, Luis will have
ss7ja [257]

Answer:

3%

Step-by-step explanation:

3 0
2 years ago
To make a specific orange color, a painter uses 14 of a can of red paint and 12 of a can of yellow paint. Fill in each statement
Otrada [13]

Answer:  For every 1 can of red paint, the number of yellow paints used by the painter is \frac{6}{7} and

There are approximately 29 cans of yellow paints for 34 cans of red paints.

Step-by-step explanation:

Since we have given that

Number of cans of red paint = 14

Number of cans of yellow paint = 12

According to question, we have to find that for every 1 can of red paint the painter uses what number of yellow paints;

Since the ratio of red paint to yellow paint is given by

14:12\\\\7:6\\\\1:\frac{6}{7}

So, for every 1 can of red paint, the number of yellow paints used by the painter is \frac{6}{7}

Similarly,

If Number of can of red paint is used = 34

So, Number of cans of yellow paint will be

\frac{6}{7}\times 34\\\\=\frac{6\times 34}{7}\\\\=29\ approx.

Hence, there are approximately 29 cans of yellow paints for 34 cans of red paints.

3 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
I forgot how to find x
GuDViN [60]
You would do 2x-3+x+3x-15=360
combine like terms which then gives you 
5x-18=360 then you would add 18 to both sides giving you
5x=378 
and then you divide by 5 on both sides which will then give you your answer x=?
6 0
3 years ago
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