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Leni [432]
2 years ago
6

What are the roots for the quadratic equation below? 3x^2+9x-2=0

Mathematics
1 answer:
Kobotan [32]2 years ago
6 0

Answer:

(-3.028, 0) (.208, 0)

Step-by-step explanation:

You would plug in the quadratic equation or you would use a calculator to solve the following equation.

You might be interested in
Factor completely 8x5 2x4 4x2. Prime 2(4x5 x4 2x2) 2x(4x4 x3 2x) 2x2(4x3 x2 2).
Alecsey [184]

The complete factor of the expression \rm 8x^5 + 2x^4 + 4x^2 is \rm 2x^{2} (4x^3 + x^2 + 2 )correct option is D.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The expression is \rm 8x^5 + 2x^4 + 4x^2.

To solve the expression properly we have to take common (2x²). Then we have

\rm 8x^5 + 2x^4 + 4x^2\\\\2x^{2} (4x^3 + x^2 + 2 )

The factor is \rm 2x^{2} (4x^3 + x^2 + 2 ).

More about the factorization link is given below.

brainly.com/question/6810544

4 0
2 years ago
Is the ratio 3:4 the same as 4:5
Georgia [21]

Answer:

No the ratio 3:4 is not equal to 4:5

Step-by-step explanation:

3:4 = 3/4 and 4:5 = 4/5

3/4 is equal to 0.75 and 4/5 is equal to 0.8

0.75 \neq 0.8

therefore, 3:4 \neq 4:5

Hope this helps!

4 0
3 years ago
If the sum of any two number is 20 and difference is 10 find the numbers​
Tanya [424]

"The sum of two numbers is 20" can be translated mathematically into the equation:

x + y = 20.

"... and their difference is 10" can be translated mathematically as:

x - y = 10

We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:

Adding the two equations will eliminate the variable y:

x + y = 20

x - y = 10

-----------

2x + 0 = 30

2x = 30

(2x)/2 = 30/2

(2/2)x = 15

(1)x = 15

x = 15

Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):

x + y = 20

15 + y = 20

15 - 15 + y = 20 - 15

0 + y = 5

y = 5

CHECK:

In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:

x + y = 20 x - y = 10

15 + 5 = 20 15 - 5 = 10

20 = 20 10 = 10

Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:

xy = 15(5)

xy = 75

6 0
3 years ago
What is the 10th 53rd &amp; 200th Figure if the constant difference is +4
natulia [17]

Answer:

Step-by-step explanation:

Assuming we are doing an arithmetic sequence

It depends on where you start

If the first term is a₁ and the term number is n

each subsequent term is

aₙ = a₁ + 4(n - 1)

a₁₀ = a₁ + 4(10 - 1) = a₁ + 36

a₅₃ = a₁ + 4(53 - 1) = a₁ + 208

a₂₀₀ = a₁ + 4(200 - 1) = a₁ + 796

7 0
3 years ago
#10 PLEASE I BEGGGGG
Aneli [31]
I cant directly give u the answer but here is some help:

for part a add up and solve the equazions on the whiteboard.

for part b subtract 90 from what you got from part a.


Hope this helps. Sorry i couldnt help more.
4 0
3 years ago
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