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MrRissso [65]
2 years ago
15

A satellite orbits the Earth with an elliptical orbit modeled by x squared over 43 million eight hundred twenty four thousand fo

ur hundred plus y squared over forty seven million one hundred ninety six thousand nine hundred equals 1 comma where the distances are measured in km. The Earth shares the same center as the orbit. If the radius of the Earth is 6,370 km, what is the maximum distance between the satellite and the Earth?
250 km
500 km
6,620 km
6,870 km
Mathematics
2 answers:
morpeh [17]2 years ago
7 0

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is

D= 510 km. Option B. This is further explained below.

<h3>What is Kepler Orbit?</h3>

Generally, In the study of astrodynamics, an ellipse of the satellite is often referred to as a Kepler Orbit

The function of the elliptical orbit is

\frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1

compared to

\frac{(x^2)^2}{47334400}+\frac{(y^2)^2}{43956900}=1

Hence

a = √(47,334,400 km²)

a= 6,880 km.

In conclusion, The distance of the satellite above the Earth's surface.

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Read more about elliptical orbit

at brainly.com/question/13999216

#SPJ1

xz_007 [3.2K]2 years ago
7 0

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is D= 510 km. Option B.

<h3>What is Elliptical Orbit?</h3>

An elliptic orbit or elliptical orbit is a Kepler orbit with an eccentricity of less than 1; this includes the special case of a circular orbit, with eccentricity equal to 0.

The function of the elliptical orbit is

\frac{{(x-h)}^2}{a^2}+  \frac{{(y-k)}^2}{b^2} = 1

compared to

  √(\frac{({x^2)}^2}{47,334,400} + \frac{({y^2)}^2}{43956900} = 1

a = √(47,334,400 km²)

a= 6,880 km.

Now,

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Learn more about elliptical orbit from:

brainly.com/question/13999216

#SPJ1

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Please answer immediately!!!!!!!!
Westkost [7]

Answer:

For tree see picture but instead of BG replace all values with RRBBB and see the notes above how to roate the colours instead of the shape roation below just do transition (0,0)(1,0) (1,1).

Then 13 colours minimum change.

This will be 3 + 5 + 4 each colour change = 12 each colour change. instead of doing the 56 each colour rotation below.

Step-by-step explanation:

make 4 bits of paper and label each side -1 and 1 and central 0

above central point vertically label 1 and -1 for transition.

Then change just top one 4x = 4 more

Do the same with 2nd from top = 8 more to include top changing 4x again.

Do the same with 2nd from bottom = 12 more

Do the same with bottom = 16 more.

4+8+12+16 =40

Then repeat the process on side for blocks and we can double up

40+40 = 80.

When drawing tree clearly state columns

Top two are red only change

Top of tree will read in order so where ever you see capital R you will know its a new column for the tree and fill in when you understand the 254 transitions of a 5 column tree. Then change B + R accordingly when you get to row 6. Here you just start changing blue back to the top after row 5

Columns go down and rows go across its a new row you will need

approx 5-6 rows each colour change.

For the ones started for you below its just transition and colour stays where it is.  

R x    RT 45d   RT (1,0) 45   RT (1,1) 45  RT (1,0)

R x    R x

B x    B x

B x    B x

B x    B x

'x' = RED Normal as you keep 0 zero central on all 4 bricks and work with top row as explained below.

Top RED  brick you have to Right side place transition on every 2nd column for each colour and thenyou should find a pattern if youve numbered your papers or brcks to just see how it works. (hanging out one side call this 'off set' or call it T for transition (1.0)

RED Central 'diagonal' call it  '45 degree rotate'

E ABCD RED Normal edge transition its edge so it hangs out

E ABCD RED On edge 45 degree diagonal its edge so it hangs out

2nd only change

S ABCD 1st red normal 2nd red Right side place rotate

S ABCD 1st red right side rotate 2nd red 45 degree rotate

S ABCD 1st red right side rotate 2nd central place 45 degree rotate  

S ABCD 1st red right side rotate 2nd edge Normal edge transition

S ABCD 1st red right side rotate 2nd 45 degree its edge diagonal

2nd is repeated by changing 1st 4x more in bold. see what is now missing for 1st red. and copy the 2nd changes to 1st all whilst rotaing 2nd again in change .

Copy paste the work

Then apply this to 3 + 4 + 5th brick.

As the above shows 10 and when you finish 2nd and 1st it will be 14 total

Then 3 will be 14 again

and 4th brick will be 14 again

and 5th brick will be 14 again

making the transitions and rotations where all bricks in same level placement

14 x 4 = 56 transitions/rotations

Then repeat again for 1 blue at the top change

Then repeat again for 2 blue at the top for change

Then repeat again for 2 blue in the top middle

Then repeat again for 2 blue in the bottom middle

You can label tree

RR = Red rotation

BR = Blue rotation

RRE= Red rotation edge

BRE = Blue rotation

and colour code blue and red pens.

You can label transitions

RT = red transition (1,0)

RT = red transition (1,1) for central

and same for blue etc..

The end result will be 56 x 4 = 224 diagram tree

On ce you learn this it will take just 6 minutes to write out.

6 0
3 years ago
One part of Clare’s job at an environmental awareness organization is to answer the phone to collect donations. The table shows
Arisa [49]

Answer:

One part of Clare’s job at an environmental awareness organization is to answer the phone to collect donations. The table shows the number of hours she worked each week, , and the amount of donations in dollars, , that the organization collected each week for 10 weeks.

Step-by-step explanation:

u.w.u

6 0
2 years ago
a 76 inch pipe is cut into two pieces One piece is three times the length of the other find the lengh of the shorter piece?
SOVA2 [1]

Answer:

/

Step-by-step explanation:

5 0
3 years ago
Jake plans to take a summer job at the recreation center as a lifeguard. He can be paid according to two different plans.
Jlenok [28]

Payment on Plan A = $300

x is the number of hours Jake works.

Payment on Plan B = Fixed charges + (charge per hour) × (number of hours worked)

                               = $150 + $6.25(x)

                               = 150 + 6.25x

Since, the payment on Plan B should be more than Plan A,

150 + 6.25x > 300

6.25x > 300 - 150

6.25x > 150

x > \frac{150}{6.25}

x > 24

The minimum vale for x which satisfies this inequality is 25.

Hence, x = 25.

5 0
3 years ago
Help with math hw (geomtry)
valkas [14]

Answer:

8

Angle 1= RQS and STU

Angle 2= RSQ and TSU

Similar due to Angle Angle

9

15:24

15x=7

24x= 7/15*14= 11.2

10.

10:2

15=10x

2x=3

11.

20:8

8x=10

x=5/4

15-4-5=5/4.

7 0
3 years ago
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