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Sergeeva-Olga [200]
3 years ago
8

Solve for x 2-3(2x-1)=-6x+5

Mathematics
1 answer:
Simora [160]3 years ago
6 0
Step 1: Simplify both sides of the equation.
2
−
3
(
2
x
−
1
)
=
−
6
x
+
5
2
+
(
−
3
)
(
2
x
)
+
(
−
3
)
(
−
1
)
=
−
6
x
+
5
(Distribute)
2
+
−
6
x
+
3
=
−
6
x
+
5
(
−
6
x
)
+
(
2
+
3
)
=
−
6
x
+
5
(Combine Like Terms)
−
6
x
+
5
=
−
6
x
+
5
−
6
x
+
5
=
−
6
x
+
5
Step 2: Add 6x to both sides.
−
6
x
+
5
+
6
x
=
−
6
x
+
5
+
6
x
5
=
5
Step 3: Subtract 5 from both sides.
5
−
5
=
5
−
5
0
=
0
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a salesperson earns 9 commission on sales.the equation for the amount he or she earns in commission is c = 0.9s, where s is the
NNADVOKAT [17]

Answer:

c = $5,400

Step-by-step explanation:

Given:

c = 0.9s

where,

s = amount sold

c = commission on sales

How much commission will he or she earn if the amount sold is $6,000?

Find c when she = $6,000

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= 5,400

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Suppose Joe earned three times as much as Marty during the summer.Together they earned 210.How much did each earn?
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7 0
3 years ago
Find the radius of the circle with equation x²+y²+8x+8y+28=0
galina1969 [7]
<h2>Hello!</h2>

The answer is:

Center: (-4,-4)

Radius: 2 units.

<h2>Why?</h2>

To solve the problem, using the given formula of a circle, we need to find its standard equation form which is equal to:

(x-h)^{2}+(y-k)^{2}=r^{2}

Where:

"h" and "k" are the coordinates of the center of the circle and "r" is its radius.

So, we need to complete the square for both variable "x" and "y".

The given equation is:

x^{2}+y^{2}+8x+8y+28=0

So, solving we have:

x^{2}+y^{2}+8x+8y=-28

(x^2+8x+(\frac{8}{2})^{2})+(y^2+8y+(\frac{8}{2})^{2})=-28+((\frac{8}{2})^{2})++(\frac{8}{2})^{2})\\\\(x^2+8x+16 )+(y^2+8y+16)=-28+16+16\\\\(x^2+4)+(y^2+4)=4

(x^2-(-4))+(y^2-(-4))=4

Now, we have that:

h=-4\\k=-4\\r=\sqrt{4}=2

So,

Center: (-4,-4)

Radius: 2 units.

Have a nice day!

Note: I have attached a picture for better understanding.

3 0
3 years ago
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