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Leviafan [203]
3 years ago
6

Write 357 over 10000 as a decimal

Mathematics
2 answers:
ipn [44]3 years ago
4 0
357/10000

= 0.357/10   ( jumping the decimal point according to zeroes)

= 0.0357 ( jumping the decimal point.

Thus, 357/10000 = 0.0357 
Vadim26 [7]3 years ago
3 0
357/10000 = 3.57/100
0.0357 into decimal

OR

Just divide :)<span />
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N+3/4=1/4 solve for n
Hitman42 [59]

Answer:

N = -1/2

Step-by-step explanation:

We are adding in this, so we need to do the opposite to both sides, to get N by itself.

N + 3/4 - 3/4 = 1/4 - 3/4

N = -2/4 or, simplified, -1/2

6 0
2 years ago
_____ have congruent corresponding parts.
aniked [119]

Answer:

Two congruent figures

Step-by-step explanation:

Here we have to use the definition of congruent.

Congruent means equal to each other.

Example.

If the two triangles said be congruent, their corresponding angles and corresponding sides are equal.

They will have to same size of the sides and same measure of angles.

Two equal polygons, that is two congruent figures.

Hope this will help you.

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4 0
3 years ago
NEED HELP ASAP! Plz answer all the questions! Including the one on the picture! Will give brainlest!
xeze [42]

-2/3-(-1 1/3) =

-2/3 + 1 1/3 =

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<em>2/3</em>

12 - (-5) =

12 + 5 =

<em>17</em>

-1 - (-6) =

-1 + 6 =

6 - 1 =

<em>5</em>

-3 3/8 - 7/8 =

27/8 - 7/8 =

20/8 =

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4 0
2 years ago
Read 2 more answers
You are working in a primary care office. Flu season is starting. For the sake of public health, it is critical to diagnose peop
Aleksandr-060686 [28]

Answer:

E. 0.11

Step-by-step explanation:

We have these following probabilities:

A 10% probability that a person has the flu.

A 90% probability that a person does not have the flu, just a cold.

If a person has the flu, a 99% probability of having a runny nose.

If a person just has a cold, a 90% probability of having a runny nose.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem, we have that:

What is the probability that a person has the flu, given that she has a runny nose?

P(B) is the probability that a person has the flu. So P(B) = 0.1.

P(A/B) is the probability that a person has a runny nose, given that she has the flu. So P(A/B) = 0.99.

P(A) is the probability that a person has a runny nose. It is 0.99 of 0.1 and 0.90 of 0.90. So

P(A) = 0.99*0.1 + 0.9*0.9 = 0.909

What is the probability that this person has the flu?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.1*0.99}{0.909} = 0.1089 = 0.11

The correct answer is:

E. 0.11

5 0
3 years ago
Six times a number is three thousand six hundread what is the number
Alecsey [184]
Divide 3600 by 6 and its 600
7 0
3 years ago
Read 2 more answers
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