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Natalija [7]
1 year ago
13

What is the net percent gained or lost on a stock with goes down 20% on Monday and then goes up 20% on Tuesday? Use a negative s

ign to indicate percentage lost.
Mathematics
1 answer:
barxatty [35]1 year ago
3 0

The net percentage lost on the stock is 4%

<h3>How to determine the net percentage?</h3>

Let the value of the stock be represented with x.

When it goes down by 20% on Monday, the value is:

Value = (1 - 20%) * x

Value = 0.8x

When it goes up by 20% on Tuesday, the value is:

Value = (1 + 20%) * 0.8x

Value = 0.96x

Recall that the initial value is x.

So, the profit is:

Profit = 0.96x - x

Evaluate the difference

Profit = -0.04x

Express as percentage

Profit = -4%x

Negative value represent a percentage lost.

Hence, the net percentage lost is 4%

Read more about percentage at:

brainly.com/question/843074

#SPJ1

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45%

Step-by-step explanation:

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6 0
2 years ago
Which of the following linear systems has a solution <br> (5,0)<br> SOMEONE PLS HELPPP
Korvikt [17]

Answer:

D

Step-by-step explanation:

out of the choices

A) 2x-y=-2

3x+2y=-10

B) x+4y=3

2x+5y=3

C) 2x+3y=5

x-4y=-14

D) 3x+4y=15

x+y=5

only the system in D has a solution of x=5 and y=0

solve by substitution x+y=5 so x=5-y

plug into the other equation so 3(5-y)+4y=15

distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms

so y=0 then put that value back into the other equation

so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)

Hope this helps! :)

3 0
2 years ago
Read 2 more answers
What is the value of the 2 in 5,678.321
STALIN [3.7K]

.020 because it is 2 spots behind the decimal

7 0
3 years ago
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7 0
3 years ago
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A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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