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ludmilkaskok [199]
3 years ago
11

Write in slope-intercept form and show work: 6x + 4y = 700

Mathematics
1 answer:
Basile [38]3 years ago
4 0
6x + 4y = 800
-6x -6x
--------------------
4y = -6x + 800
÷4 ÷4 ÷4
---------------------
y = -6/4x + 200

First subtract, then divide, and then you have it. 6/4 is your slope. Your rise is -6 and your run is 4.
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A lot is in the shape of a triangle. One side is 100 ft longer than the shortest side, while the third side is 700 ft longer tha
vaieri [72.5K]

We have the next information

x= the shortest side measure

y= the second side measure

y=x+100

z= the third side measures

z=x+700

We know also that the perimeter is 2900 ft

Therefore the equation for the perimeter of the triangle will be

P=x+y+z2900=x+x+100+x+700

we sum like terms

2900=3x+800

then we isolate the x

3x=2900-8003x=2100x=\frac{2100}{3}=700

therefore

x=700ft

y=700+100=800ft

z=700+700=1400ft

The lengths of the sides of the lote are 700 ,800, and 1400 ft,

8 0
1 year ago
HELP PICTURE IS SHOWN
strojnjashka [21]
The answer is D. y=2x^2
5 0
2 years ago
Evaluate y/2x-z x=4y=3and z=2
Gwar [14]
First you plug in the missing values
y=3 x=4 z=2
3÷2×4-2
than you solve
the answer is 4
5 0
3 years ago
Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
Alchen [17]

Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

      a^{2} = c^{2} +b^{2}

a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
Read 2 more answers
What is the equation of the line with a slope (-2/3) of and passes through the point (6,2)?
arlik [135]

Answer:

This is my solution for your question

4 0
3 years ago
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