All categories

1 year ago

The table below shows how the age of a certain tree is related to the diameter

Mathematics

1 answer:

Romashka [77]1 year ago

4 0

The age of a tree when the diameter is 11 inches is 80.

The age of the tree increases by 10 with a 1 inch increase in the diameter of the trunk. This represents a linear increase.

The equation that can be used to represent the age of a tree given its diameter is :

age of the tree when the diameter is 4 inches + [(difference between 11 inches and 4 inches) x rate of change in age)

10 + (10 x 7) = 80

To learn more about linear functions, please check: brainly.com/question/26434260

#SPJ1

You might be interested in

4 and 1 over 4 divided by 1 and 7 over 8

allsm [11]

Answer:

3 and 23 Over 32

Step-by-step explanation:

Done

8 0

2 years ago

Find equations of the line that is parallel to the z-axis and passes through the midpoint between the two points (0, −4, 9) and

Lorico [155]

Answer: x = -4, y = 0.5, z = 5 +t

Hi!

The line L whose direction is parallel to vector V a passes through point A

is parametrized

$P_L = Vt + A$

Where t, is a real number, and $P_L$ is a any point on line L.

In this case the direction is that of the z-axis , so V = (0, 0, 1)

A is the midpoint between points B = (0, -4, 9) and C=(-8, 5, 1)

The midpoint is A = (B + C)/2 = (-4, 0.5, 5)

Then the line is:

$P_L = (0,0,1) t + (-4, 0.5, 5)$

The equations for each coordinate are:

$x = -4\\y = 0.5\\z = 5 + t$

7 0

3 years ago

compare 2 pentagons that jasmine drew. tell how they are alike and, identfy three ways that they are different.

fgiga [73]

Well the may not be the same by comparing the angels and the area an perimeter and shape<span />

8 0

3 years ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

2 years ago

Find the percent error in this situation<br> Estimated: 145<br> Actual value: 189

levacccp [35]

Answer:

-23.2

_____ _____

hello thre um ((_O_)) ((_O_))

/// v ///

3 0

3 years ago