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Troyanec [42]
3 years ago
13

What is the slope of a line that is perpendicular to the line y = 8x + 5?−8 -1/8 1/8 8

Mathematics
2 answers:
Sauron [17]3 years ago
8 0

Answer:

-1/8

Step-by-step explanation:

Cerrena [4.2K]3 years ago
6 0

Answer:

-1/8

Step-by-step explanation:

When slopes are perpendicular that means it's completely opposite.

The opposite of 8 is 1/8

But 8 is positive that means we have to make the pereldicular slope negative

Therefore your answer is -1/8

Hope this helps p,z mark brainliest!

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the village was polyglot. if the ratio of bilingual denizens to trilingual denizens was 14 to 3 and the denizens totaled 3400 ho
Travka [436]
Bilingual : trilingual = 14 : 3

So, ...
  trilingual : total = 3 : (14+3) = 3 : 17

The number of trilingual denizens was (3/17)*3400 = 600.
7 0
3 years ago
Please help! The question is in the image
Goshia [24]

Answer:

I am pretty sure that your answer would be 3.

Step-by-step explanation:

The reason why is because if B if half of line segment AD and AD is equal to 12, then B must be equal to 6 since half of 12 is 6. Next, since C is the mid-point for line segment BD then C must be 3 since half of 6 is 3. And finally, that means line segment BC is three since it is 1/2 of BD.

Hope this helps! :)

3 0
3 years ago
Read 2 more answers
Factor the algebraic expression 18a + 14 18a + 14 = (Factor completely.)<br>​
stich3 [128]

Answer:

You cannot factor that any more.

Step-by-step explanation:

The equation is as simple as it can be.

5 0
2 years ago
Review questions
a_sh-v [17]

Answer:

slope: -3/4    y-intercept: 3   equation: y=(-3/4)x+3

6 0
3 years ago
1. Based on the information given, can you determine that the quadrilateral must be a
zhenek [66]

<u>Solving Q1: Given BE = ED and AE = EC.</u>

Considering triangles ΔAED and ΔCEB;

1. AE = EC (given)

2. ∠AED = ∠CEB (vertical angles)

3. ED = EB (given)

ΔAED ≡ ΔCEB (Side-Angle-Side congruency of triangles)

∠DAE = ∠BCE and AD = BC (using CPCTC)

⇒ AD║BC (Converse of Alternate Interior angles theorem)


Similarly consider triangles ΔABE and ΔCDE;

1. AE = CE (given)

2. ∠BEA = ∠DEC (vertical angles)

3. BE = DE (given)

ΔABE ≡ ΔCDE (Side-Angle-Side congruency of triangles)

∠ABE = ∠CDE and AB = CD (using CPCTC)

⇒ AB║CD (Converse of Alternate Interior angles theorem)


Since we have AB║CD, AB = CD and AD║BC, AD = BC.

Therefore, quadrilateral ABCD is a parallelogram.

****************************************************************************************************

<u>Solving Q2: The parallelogram has the angle measures shown in the diagram.</u>

It is clearly visible that both the triangles are Isosceles triangles, so opposite sides in each triangle are equal.

Consider two triangles given in the problem, we have two sets of congruent angles and one included side is common in both triangles.

Using Angle-Side-Angle congruence of triangles, both the triangles would be congruent too.

Using CPCTC, we can say opposite sides of quadrilateral would be congruent.

Therefore, all sides in given quadrilateral are equal.

Hence, Given quadrilateral is a Rhombus.

7 0
3 years ago
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