Any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power. The quadratic formula to solve a quadratic equation ax2 + bx + c = 0 is x = [-b ± √(b2 - 4ac)]/2a.

Given that:

So for the triangle, the perimeter would be:

$(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4$

By solving in above equation, we get

$(x^{2} +x+3)+(x^{2} +2x-2)+(x^{2} +2x-9)=4\\\\\\\2x^{2}+5x-8=4\\\\2x^{2}+5x-12=0\\\\2(x + 4)(x - 1.5)=0\\\\ x=-4\\\\ x=1.5$

So, we take x= 1.5 and neglect -4 because we can't take negative roots of the quadratic equation.

Hence, the value of x is equal to 1.5.

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8 0

2 years ago

PLEASE HELP ASAP!!! :)

jeka57 [31]

The rule of the transformation is
(x,y)->(-y,x)
which corresponds to a 90 counterclockwise rotation about the origin,
which in turn corresponds to a 270 clockwise rotation about the origin.

Note that all rotations preserve lengths and angles, hence the image and preimage are congruent.

6 0

3 years ago

The graph of a function is shown below.<br> <br> Is the function linear?

Andre45 [30]

No it’s not linear. To be linear it has to form a straight line.

8 0

3 years ago

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