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Chemistry

1 answer:

zhannawk [14.2K]3 years ago

4 0

From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.

<h3>What is stoichiometry?</h3>

Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.

Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles

Molar mass of carbon monoxide = 12 + 16 = 28g/mol

We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.

If 1 mole of a gas occupies 22.4 L

2 moles of a gas occupies 2 moles * 22.4 L/1 mole

= 44.8 L

Learn more about stoichiometry:brainly.com/question/9743981

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alexdok [17]

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<h3>Chemical reactions</h3>

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In this case, solid gold (III) sulfide and hydrogen gas react according to the following equation:

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