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Lisa [10]
3 years ago
9

Using the periodic table and your knowledge of atomic structure. Compare the number of electrons in a carbon-12 and carbon-14

Chemistry
2 answers:
Brut [27]3 years ago
6 0
Both carbon 12 and carbon 14 have the same no. of Electrons but the difference is carbon 14 has more neutrons
lesya [120]3 years ago
6 0

Answer:

Number of electrons will be the same for C-12 and C-14 i.e. 6 electrons

Explanation:

For a given element:

Atomic number (Z) = number of protons = number of electrons -----(1)

Atomic mass (A) = number of protons + number of neutrons -----(2)

Carbon belongs to group 14 in the periodic table with an atomic number of 6. Carbon-12 and Carbon-14 are two isotopes of carbon with atomic mass 12 and 14 respectively

For carbon-12: Z = 6 and A = 12

Therefore based on equations 1 and 2

Protons = 6

Electrons = 6

Neutrons = 12 - 6 = 6

For carbon-14: Z = 6 and A = 14

Protons = 6

Electrons = 6

Neutrons = 14 - 6 =8

Therefore, the number of electrons remain the same for C-12 and C-14. They however differ in the number of neutrons

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52.0 divided by 65 g/mol gives you 0.8mol
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Which should be more viscous,polar or non polar
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3 years ago
A closed vessel system of volume 2.5 L contains a mixture of neon and fluorine. The total pressure is 3.32 atm at 0.0°C. When th
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Answer: moles of Ne = 0.149 moles

moles of F₂ = 0.221 moles

Explanation:

<em>The process occurs at costant volume.</em>

<em>Neon is a monoatomic gas, Cv =3/2R, Flourine is a diatomic gas, Cv = 5/2R</em>

n = PV/RT ; where n is total = number of moles, P is total pressure = 3.32atm, V is volume = 2.5L, R is molar gas constant = 0.08206 L-atm/mol/K = 8.314 J/mol/K, T is temperature = 0.0°C = 273.15K

n(total) = (3.32 atm)(2.5 L)/(0.08206 L-atm/mol/K)(273.15) = 0.3703 mol

For one mole heated at constant volume,

Change in entropy, ∆S = ∫dq/T = ∫(Cv/T)dT

From T1 to T2, Cvln(T2/T2) = Cvln(288.15/273.15) = 0.05346•Cv

So, for 0.3703 moles,

∆S = (0.3703 mol)(0.05346)Cv = 0.345 J/K

⇒ Cv = 17.43 J/mol/K for the Ne/F₂ mixture.

For pure Ne, Cv = (3/2)R = 1.5 • 8.314 J/mol/K = 12.471 J/mol/K

For pure F₂, Cv = (5/2)R = 2.5 • 8.314 J/mol/K = 20.785 J/mol/K

If Y is the mole fraction of Ne, Y can be determined by setting the observed entropy change (∆S) to the weighted average of the entropy changes expected for the two different gases in the mixture:

17.43 J/mol/K = Y * 12.471 J/mol/K + (1 – Y) * 20.785 J/mol/K

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<em>Y = 0.403 ; 1 – Y = 0.597</em>

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moles of F₂ = (0.597)(0.3703 mol) = 0.221 moles

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